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OPA May 15 Unix
.
Input:
ItemID,ItemName,Item Price
1,kumar,20
2,suresh,400
3,ramesh,14
4,karthick,53
5,surya,14
6,Dinesh,14
Output:
3
Solutions:
read
awk 'BEGIN{FS=",";choice;count;i}
{ if(NR==1)
{choice=$3;a[i++]=$3}
else{
a[i++]=$3;
if(choice>$3) {choice=$3;}
}
}
END{ for(j=0;j<i;j++)
{
if(a[j]==choice){
count++;
}
}
{print count}
}'
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